What is the rated current of a 630kVA transformer? The primary current on the high voltage side is 36.37A, and the secondary current on the low voltage side is 909A. These are the current values for each side, with 10kV and 0.4kV respectively!
The calculation method for the rated current on the high-voltage side of an electric power transformer is:
The rated current I is calculated as P/(1.732*U), where P is the transformer's short-circuit capacity. For a transformer with a capacity of 630 KVA, the rated current on the high-voltage side is 630/(1.732*10) = 36.37 A.
The calculation method for the rated current on the low-voltage side of a 630kVA transformer is:
The rated current I is calculated as P/(1.732*U), where P is the transformer's short-circuit capacity and U is the rated voltage on the low-voltage side of the transformer. For a 630kVA transformer, the rated current on the low-voltage side is 630/(1.732*0.4) = 909A.
630kVA transformer rated current calculation:
Transformer current calculation method: Transformer volume ÷ (rated voltage × square root of 3).
2. The primary current of the 630kVA transformer is: 630kVA / (10kV × 1.732) = 36.37A.
The secondary current of the 630kVA transformer is: 630kVA / (0.4kV × 1.732) = 909A.
Rated Current Decision Factors for a 630kVA Transformer
The current of the 630kva transformer is determined by the load.
The 600KVA distribution equipment transformer typically has a high voltage side of 10KV and a low voltage side of 0.4KV.
The transformer's rated current is equal to volume divided by (the square root of 3 times rated voltage) 600KVA, with the high voltage side rated current at 36.37A.
Low Voltage Side = 909A.
Power transformers have full-load losses and load losses. When the full-load losses are equal to the load losses, the transformer's efficiency is higher.
Typically, load is around 60% to 70% when efficiency is high.
